9v^2-18v+2=-3

Solution for 9v^2-18v+2=-3 equation:

9v^2-18v+2=-3

We move all terms to the left:

9v^2-18v+2-(-3)=0

We add all the numbers together, and all the variables

9v^2-18v+5=0

a = 9; b = -18; c = +5;
Δ = b2-4ac
Δ = -182-4·9·5
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-12}{2*9}=\frac{6}{18}
=1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+12}{2*9}=\frac{30}{18}
=1+2/3
$